Seth bought some oranges and grapefruits in the ratio of 3 : 8 respectively. The cost of one orange was $1.50 more than the cost of one grapefruit. He spent a total of $150 buying the oranges and grapefruits. The total cost of the grapefruits was $42 more than the total cost of the oranges. How much did one grapefruit cost?
| |
Oranges |
Grapefruits |
Total |
| Number |
3 sets |
8 sets |
|
| Value |
$1.50 more |
|
|
| Total value |
|
$42 more |
$150 |
Total cost of oranges
= (150 - 42) ÷ 2
= 108 ÷ 2
= $54
Total cost of grapefruits
= 54 + 42
= $96
3 sets of oranges = $54
1 set of oranges = 54 ÷ 3 = $18
8 sets of grapefruits = $96
1 set of grapefruits = 96 ÷ 8 = $12
Difference in cost of 1 set of oranges and 1 set of grapefruits
= 18 - 12
= $6
Number of fruits in 1 set
= 6 ÷ 1.50
= 4
Cost of one grapefruit
= 12 ÷ 4
= $3
Answer(s): $3
