Will bought some plums and papayas in the ratio of 3 : 8 respectively. The cost of one plum was $1.60 more than the cost of one papaya. He spent a total of $134 buying the plums and papayas. The total cost of the papayas was $26 more than the total cost of the plums. How much did one papaya cost?
| |
Plums |
Papayas |
Total |
| Number |
3 sets |
8 sets |
|
| Value |
$1.60 more |
|
|
| Total value |
|
$26 more |
$134 |
Total cost of plums
= (134 - 26) ÷ 2
= 108 ÷ 2
= $54
Total cost of papayas
= 54 + 26
= $80
3 sets of plums = $54
1 set of plums = 54 ÷ 3 = $18
8 sets of papayas = $80
1 set of papayas = 80 ÷ 8 = $10
Difference in cost of 1 set of plums and 1 set of papayas
= 18 - 10
= $8
Number of fruits in 1 set
= 8 ÷ 1.60
= 5
Cost of one papaya
= 10 ÷ 5
= $2
Answer(s): $2
