Lee bought some dates and guavas in the ratio of 3 : 8 respectively. The cost of one date was $1.50 more than the cost of one guava. He spent a total of $106 buying the dates and guavas. The total cost of the guavas was $22 more than the total cost of the dates. How much did one date cost?
| |
Dates |
Guavas |
Total |
| Number of sets |
3 sets |
8 sets |
|
| Compare each |
$1.50 more |
|
|
| Total value |
|
$22 more |
$106 |
Total cost of dates
= (106 - 22) ÷ 2
= 84 ÷ 2
= $42
Total cost of guavas
= 42 + 22
= $64
3 sets of dates = $42
1 set of dates = 42 ÷ 3 = $14
8 sets of guavas = $64
1 set of guavas = 64 ÷ 8 = $8
Difference in cost of 1 set of dates and 1 set of guavas
= 14 - 8
= $6
Number of fruits in 1 set
= 6 ÷ 1.50
= 4
Cost of one date
= 14 ÷ 4
= $3.50
Answer(s): $3.50
