Michael bought some papayas and apricots in the ratio of 3 : 7 respectively. The cost of one papaya was $0.50 more than the cost of one apricot. He spent a total of $126 buying the papayas and apricots. The total cost of the apricots was $42 more than the total cost of the papayas. How much did one papaya cost?
| |
Papayas |
Apricots |
Total |
| Number of sets |
3 sets |
7 sets |
|
| Compare each |
$0.50 more |
|
|
| Total value |
|
$42 more |
$126 |
Total cost of papayas
= (126 - 42) ÷ 2
= 84 ÷ 2
= $42
Total cost of apricots
= 42 + 42
= $84
3 sets of papayas = $42
1 set of papayas = 42 ÷ 3 = $14
7 sets of apricots = $84
1 set of apricots = 84 ÷ 7 = $12
Difference in cost of 1 set of papayas and 1 set of apricots
= 14 - 12
= $2
Number of fruits in 1 set
= 2 ÷ 0.50
= 4
Cost of one papaya
= 14 ÷ 4
= $3.50
Answer(s): $3.50
