Eric bought some plums and limes in the ratio of 2 : 7 respectively. The cost of one plum was $1.50 more than the cost of one lime. He spent a total of $72 buying the plums and limes. The total cost of the limes was $12 more than the total cost of the plums. How much did one lime cost?
| |
Plums |
Limes |
Total |
| Number |
2 sets |
7 sets |
|
| Value |
$1.50 more |
|
|
| Total value |
|
$12 more |
$72 |
Total cost of plums
= (72 - 12) ÷ 2
= 60 ÷ 2
= $30
Total cost of limes
= 30 + 12
= $42
2 sets of plums = $30
1 set of plums = 30 ÷ 2 = $15
7 sets of limes = $42
1 set of limes = 42 ÷ 7 = $6
Difference in cost of 1 set of plums and 1 set of limes
= 15 - 6
= $9
Number of fruits in 1 set
= 9 ÷ 1.50
= 6
Cost of one lime
= 6 ÷ 6
= $1
Answer(s): $1
