Brandon bought some tomatoes and limes in the ratio of 3 : 7 respectively. The cost of one tomato was $0.60 more than the cost of one lime. He spent a total of $109 buying the tomatoes and limes. The total cost of the limes was $31 more than the total cost of the tomatoes. How much did one lime cost?
| |
Tomatoes |
Limes |
Total |
| Number |
3 sets |
7 sets |
|
| Value |
$0.60 more |
|
|
| Total value |
|
$31 more |
$109 |
Total cost of tomatoes
= (109 - 31) ÷ 2
= 78 ÷ 2
= $39
Total cost of limes
= 39 + 31
= $70
3 sets of tomatoes = $39
1 set of tomatoes = 39 ÷ 3 = $13
7 sets of limes = $70
1 set of limes = 70 ÷ 7 = $10
Difference in cost of 1 set of tomatoes and 1 set of limes
= 13 - 10
= $3
Number of fruits in 1 set
= 3 ÷ 0.60
= 5
Cost of one lime
= 10 ÷ 5
= $2
Answer(s): $2
