Elijah bought some oranges and papayas in the ratio of 3 : 7 respectively. The cost of one orange was $1.50 more than the cost of one papaya. He spent a total of $207 buying the oranges and papayas. The total cost of the papayas was $45 more than the total cost of the oranges. How much did one orange cost?
| |
Oranges |
Papayas |
Total |
| Number of sets |
3 sets |
7 sets |
|
| Compare each |
$1.50 more |
|
|
| Total value |
|
$45 more |
$207 |
Total cost of oranges
= (207 - 45) ÷ 2
= 162 ÷ 2
= $81
Total cost of papayas
= 81 + 45
= $126
3 sets of oranges = $81
1 set of oranges = 81 ÷ 3 = $27
7 sets of papayas = $126
1 set of papayas = 126 ÷ 7 = $18
Difference in cost of 1 set of oranges and 1 set of papayas
= 27 - 18
= $9
Number of fruits in 1 set
= 9 ÷ 1.50
= 6
Cost of one orange
= 27 ÷ 6
= $4.50
Answer(s): $4.50
