Lee and Kathy has some money each. If Kathy gives Lee $11, he will have 5 times as much money as her. If Lee gives Kathy $16, he will have the same amount of money as her. How much money does each person have respectively?
- Lee?
- Kathy?
|
Case 1 |
Case 2 |
|
Lee |
Kathy |
Lee |
Kathy |
Before |
5 u - 11 |
1 u + 11 |
3 u + 16 |
3 u - 16 |
Change |
+ 11 |
- 11 |
- 16 |
+ 16 |
After |
5 u |
1 u |
3 u |
3 u |
(a)
If Kathy gives Lee some money or Lee gives Kathy some money, the total amount of money remains the same.
Total amount that Lee and Kathy have in the end for both cases
= 5 u + 1 u
= 6 u
Amount that Lee and Kathy each has in the end in Case 2
= 6 u ÷ 2
= 3 u
The amount that Lee has at first in Case 1 and Case 2 is the same.
5 u - 11 = 3 u + 16
5 u - 3 u = 16 + 11
1 u = 27
Amount that Lee has
= 3 u + 16
= 3 x 27 + 16
= 81 + 16
= $97
(b)
Amount that Kathy has
= 1 u + 11
= 27 + 11
= $38
Answer(s): (a) $97; (b) $38