Sean and Jaslyn has some money each. If Jaslyn gives Sean $14, he will have 7 times as much money as her. If Sean gives Jaslyn $16, he will have the same amount of money as her. How much money does each person have respectively?

1. Sean?
2. Jaslyn?

	Case 1		Case 2
	Sean	Jaslyn	Sean	Jaslyn
Before	7 u - 14	1 u + 14	4 u + 16	4 u - 16
Change	+ 14	- 14	- 16	+ 16
After	7 u	1 u	4 u	4 u

(a)
If Jaslyn gives Sean some money or Sean gives Jaslyn some money, the total amount of money remains the same.  

Total amount that Sean and Jaslyn have in the end for both cases
= 7 u + 1 u
= 8 u

Amount that Sean and Jaslyn each has in the end in Case 2
= 8 u ÷ 2
= 4 u

The amount that Sean has at first in Case 1 and Case 2 is the same.
7 u - 14 = 4 u + 16
7 u - 4 u = 16 + 14

1 u = 30

Amount that Sean has
= 4 u + 16
= 4 x 30 + 16
= 120 + 16
= $136

(b)
Amount that Jaslyn has
= 1 u + 14
= 30 + 14
= $44

Answer(s): (a) $136; (b) $44