Cody and Min has some money each. If Min gives Cody $16, he will have 3 times as much money as her. If Cody gives Min $11, he will have the same amount of money as her. How much money does each person have respectively?
- Cody?
- Min?
| |
Case 1 |
Case 2 |
| |
Cody |
Min |
Cody |
Min |
| Before |
3 u - 16 |
1 u + 16 |
2 u + 11 |
2 u - 11 |
| Change |
+ 16 |
- 16 |
- 11 |
+ 11 |
| After |
3 u |
1 u |
2 u |
2 u |
(a)
If Min gives Cody some money or Cody gives Min some money, the total amount of money remains the same.
Total amount that Cody and Min have in the end for both cases
= 3 u + 1 u
= 4 u
Amount that Cody and Min each has in the end in Case 2
= 4 u ÷ 2
= 2 u
The amount that Cody has at first in Case 1 and Case 2 is the same.
3 u - 16 = 2 u + 11
3 u - 2 u = 11 + 16
1 u = 27
Amount that Cody has
= 2 u + 11
= 2 x 27 + 11
= 54 + 11
= $65
(b)
Amount that Min has
= 1 u + 16
= 27 + 16
= $43
Answer(s): (a) $65; (b) $43
