Albert and Barbara has some money each. If Barbara gives Albert $15, he will have 5 times as much money as her. If Albert gives Barbara $10, he will have the same amount of money as her. How much money does each person have respectively?
- Albert?
- Barbara?
|
Case 1 |
Case 2 |
|
Albert |
Barbara |
Albert |
Barbara |
Before |
5 u - 15 |
1 u + 15 |
3 u + 10 |
3 u - 10 |
Change |
+ 15 |
- 15 |
- 10 |
+ 10 |
After |
5 u |
1 u |
3 u |
3 u |
(a)
If Barbara gives Albert some money or Albert gives Barbara some money, the total amount of money remains the same.
Total amount that Albert and Barbara have in the end for both cases
= 5 u + 1 u
= 6 u
Amount that Albert and Barbara each has in the end in Case 2
= 6 u ÷ 2
= 3 u
The amount that Albert has at first in Case 1 and Case 2 is the same.
5 u - 15 = 3 u + 10
5 u - 3 u = 10 + 15
1 u = 25
Amount that Albert has
= 3 u + 10
= 3 x 25 + 10
= 75 + 10
= $85
(b)
Amount that Barbara has
= 1 u + 15
= 25 + 15
= $40
Answer(s): (a) $85; (b) $40