Pierre and Jaslyn has some money each. If Jaslyn gives Pierre $10, he will have 5 times as much money as her. If Pierre gives Jaslyn $14, he will have the same amount of money as her. How much money does each person have respectively?

1. Pierre?
2. Jaslyn?

	Case 1		Case 2
	Pierre	Jaslyn	Pierre	Jaslyn
Before	5 u - 10	1 u + 10	3 u + 14	3 u - 14
Change	+ 10	- 10	- 14	+ 14
After	5 u	1 u	3 u	3 u

(a)
If Jaslyn gives Pierre some money or Pierre gives Jaslyn some money, the total amount of money remains the same.  

Total amount that Pierre and Jaslyn have in the end for both cases
= 5 u + 1 u
= 6 u

Amount that Pierre and Jaslyn each has in the end in Case 2
= 6 u ÷ 2
= 3 u

The amount that Pierre has at first in Case 1 and Case 2 is the same.
5 u - 10 = 3 u + 14
5 u - 3 u = 14 + 10

1 u = 24

Amount that Pierre has
= 3 u + 14
= 3 x 24 + 14
= 72 + 14
= $86

(b)
Amount that Jaslyn has
= 1 u + 10
= 24 + 10
= $34

Answer(s): (a) $86; (b) $34