Daniel and Paul have some money. If Daniel gives $181 to Paul, the ratio of their money will be 3 : 5. If Daniel gives $622 to Paul, the ratio of their money will be 1: 4. How much does Daniel have?
| |
Case 1 |
Case 2 |
| |
Daniel |
Paul |
Daniel |
Paul |
| Before |
15 u + $181 |
25 u - $181 |
8 u + $622 |
32 u - $622 |
| Change |
- $181 |
+ $181 |
- $622 |
+ $622 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Daniel has at first is the same in both cases.
15 u + 181 = 8 u + 622
15 u - 8 u = 622 - 181
7 u = 441
1 u = 441 ÷ 7 = 63
Amount that Daniel has
= 15 u + 181
= 15 x 63 + 181
= 945 + 181
= $1126
Answer(s): $1126
