Luis and Oliver have some money. If Luis gives $141 to Oliver, the ratio of their money will be 2 : 5. If Luis gives $567 to Oliver, the ratio of their money will be 1: 4. How much does Luis have?
| |
Case 1 |
Case 2 |
| |
Luis |
Oliver |
Luis |
Oliver |
| Before |
10 u + $141 |
25 u - $141 |
7 u + $567 |
28 u - $567 |
| Change |
- $141 |
+ $141 |
- $567 |
+ $567 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Luis has at first is the same in both cases.
10 u + 141 = 7 u + 567
10 u - 7 u = 567 - 141
3 u = 426
1 u = 426 ÷ 3 = 142
Amount that Luis has
= 10 u + 141
= 10 x 142 + 141
= 1420 + 141
= $1561
Answer(s): $1561
