Jenson and Zane have some money. If Jenson gives $377 to Zane, the ratio of their money will be 2 : 5. If Jenson gives $521 to Zane, the ratio of their money will be 1: 4. How much does Jenson have?
| |
Case 1 |
Case 2 |
| |
Jenson |
Zane |
Jenson |
Zane |
| Before |
10 u + $377 |
25 u - $377 |
7 u + $521 |
28 u - $521 |
| Change |
- $377 |
+ $377 |
- $521 |
+ $521 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Jenson has at first is the same in both cases.
10 u + 377 = 7 u + 521
10 u - 7 u = 521 - 377
3 u = 144
1 u = 144 ÷ 3 = 48
Amount that Jenson has
= 10 u + 377
= 10 x 48 + 377
= 480 + 377
= $857
Answer(s): $857
