Jenson and Cole have some money. If Jenson gives $272 to Cole, the ratio of their money will be 2 : 5. If Jenson gives $680 to Cole, the ratio of their money will be 1: 4. How much does Jenson have?
| |
Case 1 |
Case 2 |
| |
Jenson |
Cole |
Jenson |
Cole |
| Before |
10 u + $272 |
25 u - $272 |
7 u + $680 |
28 u - $680 |
| Change |
- $272 |
+ $272 |
- $680 |
+ $680 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Jenson has at first is the same in both cases.
10 u + 272 = 7 u + 680
10 u - 7 u = 680 - 272
3 u = 408
1 u = 408 ÷ 3 = 136
Amount that Jenson has
= 10 u + 272
= 10 x 136 + 272
= 1360 + 272
= $1632
Answer(s): $1632
