Cole and Lee have some money. If Cole gives $398 to Lee, the ratio of their money will be 3 : 5. If Cole gives $468 to Lee, the ratio of their money will be 1: 4. How much does Cole have?
| |
Case 1 |
Case 2 |
| |
Cole |
Lee |
Cole |
Lee |
| Before |
15 u + $398 |
25 u - $398 |
8 u + $468 |
32 u - $468 |
| Change |
- $398 |
+ $398 |
- $468 |
+ $468 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Cole has at first is the same in both cases.
15 u + 398 = 8 u + 468
15 u - 8 u = 468 - 398
7 u = 70
1 u = 70 ÷ 7 = 10
Amount that Cole has
= 15 u + 398
= 15 x 10 + 398
= 150 + 398
= $548
Answer(s): $548
