Julian and Seth have some money. If Julian gives $155 to Seth, the ratio of their money will be 2 : 5. If Julian gives $452 to Seth, the ratio of their money will be 1: 4. How much does Julian have?
| |
Case 1 |
Case 2 |
| |
Julian |
Seth |
Julian |
Seth |
| Before |
10 u + $155 |
25 u - $155 |
7 u + $452 |
28 u - $452 |
| Change |
- $155 |
+ $155 |
- $452 |
+ $452 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Julian has at first is the same in both cases.
10 u + 155 = 7 u + 452
10 u - 7 u = 452 - 155
3 u = 297
1 u = 297 ÷ 3 = 99
Amount that Julian has
= 10 u + 155
= 10 x 99 + 155
= 990 + 155
= $1145
Answer(s): $1145
