Ken and Lee have some money. If Ken gives $130 to Lee, the ratio of their money will be 2 : 5. If Ken gives $469 to Lee, the ratio of their money will be 1: 4. How much does Ken have?
| |
Case 1 |
Case 2 |
| |
Ken |
Lee |
Ken |
Lee |
| Before |
10 u + $130 |
25 u - $130 |
7 u + $469 |
28 u - $469 |
| Change |
- $130 |
+ $130 |
- $469 |
+ $469 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Ken has at first is the same in both cases.
10 u + 130 = 7 u + 469
10 u - 7 u = 469 - 130
3 u = 339
1 u = 339 ÷ 3 = 113
Amount that Ken has
= 10 u + 130
= 10 x 113 + 130
= 1130 + 130
= $1260
Answer(s): $1260
