Jenson and Howard have some money. If Jenson gives $231 to Howard, the ratio of their money will be 3 : 5. If Jenson gives $546 to Howard, the ratio of their money will be 1: 4. How much does Jenson have?
| |
Case 1 |
Case 2 |
| |
Jenson |
Howard |
Jenson |
Howard |
| Before |
15 u + $231 |
25 u - $231 |
8 u + $546 |
32 u - $546 |
| Change |
- $231 |
+ $231 |
- $546 |
+ $546 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Jenson has at first is the same in both cases.
15 u + 231 = 8 u + 546
15 u - 8 u = 546 - 231
7 u = 315
1 u = 315 ÷ 7 = 45
Amount that Jenson has
= 15 u + 231
= 15 x 45 + 231
= 675 + 231
= $906
Answer(s): $906
