Cody and Carl have some money. If Cody gives $189 to Carl, the ratio of their money will be 3 : 5. If Cody gives $581 to Carl, the ratio of their money will be 1: 4. How much does Cody have?
| |
Case 1 |
Case 2 |
| |
Cody |
Carl |
Cody |
Carl |
| Before |
15 u + $189 |
25 u - $189 |
8 u + $581 |
32 u - $581 |
| Change |
- $189 |
+ $189 |
- $581 |
+ $581 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Cody has at first is the same in both cases.
15 u + 189 = 8 u + 581
15 u - 8 u = 581 - 189
7 u = 392
1 u = 392 ÷ 7 = 56
Amount that Cody has
= 15 u + 189
= 15 x 56 + 189
= 840 + 189
= $1029
Answer(s): $1029
