Brandon and Luke have some money. If Brandon gives $136 to Luke, the ratio of their money will be 2 : 5. If Brandon gives $487 to Luke, the ratio of their money will be 1: 4. How much does Brandon have?
| |
Case 1 |
Case 2 |
| |
Brandon |
Luke |
Brandon |
Luke |
| Before |
10 u + $136 |
25 u - $136 |
7 u + $487 |
28 u - $487 |
| Change |
- $136 |
+ $136 |
- $487 |
+ $487 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Brandon has at first is the same in both cases.
10 u + 136 = 7 u + 487
10 u - 7 u = 487 - 136
3 u = 351
1 u = 351 ÷ 3 = 117
Amount that Brandon has
= 10 u + 136
= 10 x 117 + 136
= 1170 + 136
= $1306
Answer(s): $1306
