Brandon and Ken have some money. If Brandon gives $303 to Ken, the ratio of their money will be 2 : 5. If Brandon gives $651 to Ken, the ratio of their money will be 1: 4. How much does Brandon have?
| |
Case 1 |
Case 2 |
| |
Brandon |
Ken |
Brandon |
Ken |
| Before |
10 u + $303 |
25 u - $303 |
7 u + $651 |
28 u - $651 |
| Change |
- $303 |
+ $303 |
- $651 |
+ $651 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Brandon has at first is the same in both cases.
10 u + 303 = 7 u + 651
10 u - 7 u = 651 - 303
3 u = 348
1 u = 348 ÷ 3 = 116
Amount that Brandon has
= 10 u + 303
= 10 x 116 + 303
= 1160 + 303
= $1463
Answer(s): $1463
