Albert and Jeremy have some money. If Albert gives $244 to Jeremy, the ratio of their money will be 3 : 5. If Albert gives $636 to Jeremy, the ratio of their money will be 1: 4. How much does Albert have?
| |
Case 1 |
Case 2 |
| |
Albert |
Jeremy |
Albert |
Jeremy |
| Before |
15 u + $244 |
25 u - $244 |
8 u + $636 |
32 u - $636 |
| Change |
- $244 |
+ $244 |
- $636 |
+ $636 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Albert has at first is the same in both cases.
15 u + 244 = 8 u + 636
15 u - 8 u = 636 - 244
7 u = 392
1 u = 392 ÷ 7 = 56
Amount that Albert has
= 15 u + 244
= 15 x 56 + 244
= 840 + 244
= $1084
Answer(s): $1084
