Cole and Jack have some money. If Cole gives $211 to Jack, the ratio of their money will be 2 : 5. If Cole gives $505 to Jack, the ratio of their money will be 1: 4. How much does Cole have?
| |
Case 1 |
Case 2 |
| |
Cole |
Jack |
Cole |
Jack |
| Before |
10 u + $211 |
25 u - $211 |
7 u + $505 |
28 u - $505 |
| Change |
- $211 |
+ $211 |
- $505 |
+ $505 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Cole has at first is the same in both cases.
10 u + 211 = 7 u + 505
10 u - 7 u = 505 - 211
3 u = 294
1 u = 294 ÷ 3 = 98
Amount that Cole has
= 10 u + 211
= 10 x 98 + 211
= 980 + 211
= $1191
Answer(s): $1191
