Peter and Dylan have some money. If Peter gives $186 to Dylan, the ratio of their money will be 3 : 5. If Peter gives $655 to Dylan, the ratio of their money will be 1: 4. How much does Peter have?
| |
Case 1 |
Case 2 |
| |
Peter |
Dylan |
Peter |
Dylan |
| Before |
15 u + $186 |
25 u - $186 |
8 u + $655 |
32 u - $655 |
| Change |
- $186 |
+ $186 |
- $655 |
+ $655 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Peter has at first is the same in both cases.
15 u + 186 = 8 u + 655
15 u - 8 u = 655 - 186
7 u = 469
1 u = 469 ÷ 7 = 67
Amount that Peter has
= 15 u + 186
= 15 x 67 + 186
= 1005 + 186
= $1191
Answer(s): $1191
