Cody and Sean have some money. If Cody gives $146 to Sean, the ratio of their money will be 2 : 5. If Cody gives $578 to Sean, the ratio of their money will be 1: 4. How much does Cody have?
| |
Case 1 |
Case 2 |
| |
Cody |
Sean |
Cody |
Sean |
| Before |
10 u + $146 |
25 u - $146 |
7 u + $578 |
28 u - $578 |
| Change |
- $146 |
+ $146 |
- $578 |
+ $578 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Cody has at first is the same in both cases.
10 u + 146 = 7 u + 578
10 u - 7 u = 578 - 146
3 u = 432
1 u = 432 ÷ 3 = 144
Amount that Cody has
= 10 u + 146
= 10 x 144 + 146
= 1440 + 146
= $1586
Answer(s): $1586
