Julian and Sean have some money. If Julian gives $353 to Sean, the ratio of their money will be 2 : 5. If Julian gives $488 to Sean, the ratio of their money will be 1: 4. How much does Julian have?
| |
Case 1 |
Case 2 |
| |
Julian |
Sean |
Julian |
Sean |
| Before |
10 u + $353 |
25 u - $353 |
7 u + $488 |
28 u - $488 |
| Change |
- $353 |
+ $353 |
- $488 |
+ $488 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Julian has at first is the same in both cases.
10 u + 353 = 7 u + 488
10 u - 7 u = 488 - 353
3 u = 135
1 u = 135 ÷ 3 = 45
Amount that Julian has
= 10 u + 353
= 10 x 45 + 353
= 450 + 353
= $803
Answer(s): $803
