Xavier and Cody have some money. If Xavier gives $332 to Cody, the ratio of their money will be 3 : 5. If Xavier gives $626 to Cody, the ratio of their money will be 1: 4. How much does Xavier have?
| |
Case 1 |
Case 2 |
| |
Xavier |
Cody |
Xavier |
Cody |
| Before |
15 u + $332 |
25 u - $332 |
8 u + $626 |
32 u - $626 |
| Change |
- $332 |
+ $332 |
- $626 |
+ $626 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Xavier has at first is the same in both cases.
15 u + 332 = 8 u + 626
15 u - 8 u = 626 - 332
7 u = 294
1 u = 294 ÷ 7 = 42
Amount that Xavier has
= 15 u + 332
= 15 x 42 + 332
= 630 + 332
= $962
Answer(s): $962
