Simon and Luis have some money. If Simon gives $183 to Luis, the ratio of their money will be 2 : 5. If Simon gives $666 to Luis, the ratio of their money will be 1: 4. How much does Simon have?
| |
Case 1 |
Case 2 |
| |
Simon |
Luis |
Simon |
Luis |
| Before |
10 u + $183 |
25 u - $183 |
7 u + $666 |
28 u - $666 |
| Change |
- $183 |
+ $183 |
- $666 |
+ $666 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Simon has at first is the same in both cases.
10 u + 183 = 7 u + 666
10 u - 7 u = 666 - 183
3 u = 483
1 u = 483 ÷ 3 = 161
Amount that Simon has
= 10 u + 183
= 10 x 161 + 183
= 1610 + 183
= $1793
Answer(s): $1793
