Ian and Luis have some money. If Ian gives $262 to Luis, the ratio of their money will be 3 : 5. If Ian gives $465 to Luis, the ratio of their money will be 1: 4. How much does Ian have?
| |
Case 1 |
Case 2 |
| |
Ian |
Luis |
Ian |
Luis |
| Before |
15 u + $262 |
25 u - $262 |
8 u + $465 |
32 u - $465 |
| Change |
- $262 |
+ $262 |
- $465 |
+ $465 |
After
|
3x5 =
15 u |
5x5 =
25 u |
1x8 =
8 u |
4x8 =
32 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 8 and 5 is 40.
The amount that Ian has at first is the same in both cases.
15 u + 262 = 8 u + 465
15 u - 8 u = 465 - 262
7 u = 203
1 u = 203 ÷ 7 = 29
Amount that Ian has
= 15 u + 262
= 15 x 29 + 262
= 435 + 262
= $697
Answer(s): $697
