Jenson and Xavier have some money. If Jenson gives $329 to Xavier, the ratio of their money will be 2 : 5. If Jenson gives $476 to Xavier, the ratio of their money will be 1: 4. How much does Jenson have?
| |
Case 1 |
Case 2 |
| |
Jenson |
Xavier |
Jenson |
Xavier |
| Before |
10 u + $329 |
25 u - $329 |
7 u + $476 |
28 u - $476 |
| Change |
- $329 |
+ $329 |
- $476 |
+ $476 |
After
|
2x5 =
10 u |
5x5 =
25 u |
1x7 =
7 u |
4x7 =
28 u |
The total amounts in both cases remain unchanged. Make the total amounts in both cases the same. LCM of 7 and 5 is 35.
The amount that Jenson has at first is the same in both cases.
10 u + 329 = 7 u + 476
10 u - 7 u = 476 - 329
3 u = 147
1 u = 147 ÷ 3 = 49
Amount that Jenson has
= 10 u + 329
= 10 x 49 + 329
= 490 + 329
= $819
Answer(s): $819
