There are some black and green beads in a box. If 2 black beads are removed from the box, the total number of beads left will be 8 times the number of black beads left. If 12 green beads are removed from the box, the total number of beads left will be 6 times the number of black beads. How many beads are there in the box?
|
Case 1 |
Case 2 |
|
Black beads |
Green beads |
Black beads |
Green beads |
Before |
1 u + 2 |
7 u |
1 p |
5 p + 12 |
Change |
- 2 |
|
|
- 12 |
After |
1 u |
7 u |
1 p |
5 p |
Number of green beads in the end for Case 1
= 8 u - 1 u
= 7 u
Number of black beads in the end for Case 2
= 6 p - 1 p
= 5 p
The number of black beads at first is the same for Case 1 and Case 2.
The number of green beads at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
7 u = 5 p + 12
7 u - 12 =
5 p --- (2)
Make p the same.
(1)
x5 5 u + 10 =
5 p --- (3)
(2) = (3)
7 u - 12 = 5 u + 10
7 u - 5 u = 10 + 12
2 u = 22
1 u = 22 ÷ 2 = 11
Number of beads in the box
= (1 u + 2) + 7 u
= 8 u + 2
= (8 x 11) + 2
= 88 + 2
= 90
Answer(s): 90