There are some silver and purple marbles in a box. If 5 silver marbles are removed from the box, the total number of marbles left will be 9 times the number of silver marbles left. If 5 purple marbles are removed from the box, the total number of marbles left will be 6 times the number of silver marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Silver marbles |
Purple marbles |
Silver marbles |
Purple marbles |
Before |
1 u + 5 |
8 u |
1 p |
5 p + 5 |
Change |
- 5 |
|
|
- 5 |
After |
1 u |
8 u |
1 p |
5 p |
Number of purple marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of silver marbles in the end for Case 2
= 6 p - 1 p
= 5 p
The number of silver marbles at first is the same for Case 1 and Case 2.
The number of purple marbles at first is also the same for Case 1 and Case 2.
1 u + 5 = 1 p --- (1)
8 u = 5 p + 5
8 u - 5 =
5 p --- (2)
Make p the same.
(1)
x5 5 u + 25 =
5 p --- (3)
(2) = (3)
8 u - 5 = 5 u + 25
8 u - 5 u = 25 + 5
3 u = 30
1 u = 30 ÷ 3 = 10
Number of marbles in the box
= (1 u + 5) + 8 u
= 9 u + 5
= (9 x 10) + 5
= 90 + 5
= 95
Answer(s): 95