There are some blue and green marbles in a box. If 8 blue marbles are removed from the box, the total number of marbles left will be 9 times the number of blue marbles left. If 31 green marbles are removed from the box, the total number of marbles left will be 4 times the number of blue marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Blue marbles |
Green marbles |
Blue marbles |
Green marbles |
Before |
1 u + 8 |
8 u |
1 p |
3 p + 31 |
Change |
- 8 |
|
|
- 31 |
After |
1 u |
8 u |
1 p |
3 p |
Number of green marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of blue marbles in the end for Case 2
= 4 p - 1 p
= 3 p
The number of blue marbles at first is the same for Case 1 and Case 2.
The number of green marbles at first is also the same for Case 1 and Case 2.
1 u + 8 = 1 p --- (1)
8 u = 3 p + 31
8 u - 31 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 24 =
3 p --- (3)
(2) = (3)
8 u - 31 = 3 u + 24
8 u - 3 u = 24 + 31
5 u = 55
1 u = 55 ÷ 5 = 11
Number of marbles in the box
= (1 u + 8) + 8 u
= 9 u + 8
= (9 x 11) + 8
= 99 + 8
= 107
Answer(s): 107