There are some yellow and brown marbles in a container. If 8 yellow marbles are removed from the container, the total number of marbles left will be 6 times the number of yellow marbles left. If 2 brown marbles are removed from the container, the total number of marbles left will be 3 times the number of yellow marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Yellow marbles |
Brown marbles |
Yellow marbles |
Brown marbles |
Before |
1 u + 8 |
5 u |
1 p |
2 p + 2 |
Change |
- 8 |
|
|
- 2 |
After |
1 u |
5 u |
1 p |
2 p |
Number of brown marbles in the end for Case 1
= 6 u - 1 u
= 5 u
Number of yellow marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of yellow marbles at first is the same for Case 1 and Case 2.
The number of brown marbles at first is also the same for Case 1 and Case 2.
1 u + 8 = 1 p --- (1)
5 u = 2 p + 2
5 u - 2 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 16 =
2 p --- (3)
(2) = (3)
5 u - 2 = 2 u + 16
5 u - 2 u = 16 + 2
3 u = 18
1 u = 18 ÷ 3 = 6
Number of marbles in the container
= (1 u + 8) + 5 u
= 6 u + 8
= (6 x 6) + 8
= 36 + 8
= 44
Answer(s): 44