There are some brown and purple beads in a container. If 4 brown beads are removed from the container, the total number of beads left will be 8 times the number of brown beads left. If 20 purple beads are removed from the container, the total number of beads left will be 5 times the number of brown beads. How many beads are there in the container?
|
Case 1 |
Case 2 |
|
Brown beads |
Purple beads |
Brown beads |
Purple beads |
Before |
1 u + 4 |
7 u |
1 p |
4 p + 20 |
Change |
- 4 |
|
|
- 20 |
After |
1 u |
7 u |
1 p |
4 p |
Number of purple beads in the end for Case 1
= 8 u - 1 u
= 7 u
Number of brown beads in the end for Case 2
= 5 p - 1 p
= 4 p
The number of brown beads at first is the same for Case 1 and Case 2.
The number of purple beads at first is also the same for Case 1 and Case 2.
1 u + 4 = 1 p --- (1)
7 u = 4 p + 20
7 u - 20 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 16 =
4 p --- (3)
(2) = (3)
7 u - 20 = 4 u + 16
7 u - 4 u = 16 + 20
3 u = 36
1 u = 36 ÷ 3 = 12
Number of beads in the container
= (1 u + 4) + 7 u
= 8 u + 4
= (8 x 12) + 4
= 96 + 4
= 100
Answer(s): 100