There are some silver and white marbles in a box. If 9 silver marbles are removed from the box, the total number of marbles left will be 6 times the number of silver marbles left. If 12 white marbles are removed from the box, the total number of marbles left will be 3 times the number of silver marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Silver marbles |
White marbles |
Silver marbles |
White marbles |
Before |
1 u + 9 |
5 u |
1 p |
2 p + 12 |
Change |
- 9 |
|
|
- 12 |
After |
1 u |
5 u |
1 p |
2 p |
Number of white marbles in the end for Case 1
= 6 u - 1 u
= 5 u
Number of silver marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of silver marbles at first is the same for Case 1 and Case 2.
The number of white marbles at first is also the same for Case 1 and Case 2.
1 u + 9 = 1 p --- (1)
5 u = 2 p + 12
5 u - 12 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 18 =
2 p --- (3)
(2) = (3)
5 u - 12 = 2 u + 18
5 u - 2 u = 18 + 12
3 u = 30
1 u = 30 ÷ 3 = 10
Number of marbles in the box
= (1 u + 9) + 5 u
= 6 u + 9
= (6 x 10) + 9
= 60 + 9
= 69
Answer(s): 69