There are some purple and blue beads in a box. If 9 purple beads are removed from the box, the total number of beads left will be 9 times the number of purple beads left. If 4 blue beads are removed from the box, the total number of beads left will be 5 times the number of purple beads. How many beads are there in the box?
|
Case 1 |
Case 2 |
|
Purple beads |
Blue beads |
Purple beads |
Blue beads |
Before |
1 u + 9 |
8 u |
1 p |
4 p + 4 |
Change |
- 9 |
|
|
- 4 |
After |
1 u |
8 u |
1 p |
4 p |
Number of blue beads in the end for Case 1
= 9 u - 1 u
= 8 u
Number of purple beads in the end for Case 2
= 5 p - 1 p
= 4 p
The number of purple beads at first is the same for Case 1 and Case 2.
The number of blue beads at first is also the same for Case 1 and Case 2.
1 u + 9 = 1 p --- (1)
8 u = 4 p + 4
8 u - 4 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 36 =
4 p --- (3)
(2) = (3)
8 u - 4 = 4 u + 36
8 u - 4 u = 36 + 4
4 u = 40
1 u = 40 ÷ 4 = 10
Number of beads in the box
= (1 u + 9) + 8 u
= 9 u + 9
= (9 x 10) + 9
= 90 + 9
= 99
Answer(s): 99