There are some red and purple marbles in a container. If 10 red marbles are removed from the container, the total number of marbles left will be 6 times the number of red marbles left. If 10 purple marbles are removed from the container, the total number of marbles left will be 3 times the number of red marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Red marbles |
Purple marbles |
Red marbles |
Purple marbles |
Before |
1 u + 10 |
5 u |
1 p |
2 p + 10 |
Change |
- 10 |
|
|
- 10 |
After |
1 u |
5 u |
1 p |
2 p |
Number of purple marbles in the end for Case 1
= 6 u - 1 u
= 5 u
Number of red marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of red marbles at first is the same for Case 1 and Case 2.
The number of purple marbles at first is also the same for Case 1 and Case 2.
1 u + 10 = 1 p --- (1)
5 u = 2 p + 10
5 u - 10 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 20 =
2 p --- (3)
(2) = (3)
5 u - 10 = 2 u + 20
5 u - 2 u = 20 + 10
3 u = 30
1 u = 30 ÷ 3 = 10
Number of marbles in the container
= (1 u + 10) + 5 u
= 6 u + 10
= (6 x 10) + 10
= 60 + 10
= 70
Answer(s): 70