There are some gold and silver marbles in a container. If 3 gold marbles are removed from the container, the total number of marbles left will be 6 times the number of gold marbles left. If 3 silver marbles are removed from the container, the total number of marbles left will be 4 times the number of gold marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Gold marbles |
Silver marbles |
Gold marbles |
Silver marbles |
Before |
1 u + 3 |
5 u |
1 p |
3 p + 3 |
Change |
- 3 |
|
|
- 3 |
After |
1 u |
5 u |
1 p |
3 p |
Number of silver marbles in the end for Case 1
= 6 u - 1 u
= 5 u
Number of gold marbles in the end for Case 2
= 4 p - 1 p
= 3 p
The number of gold marbles at first is the same for Case 1 and Case 2.
The number of silver marbles at first is also the same for Case 1 and Case 2.
1 u + 3 = 1 p --- (1)
5 u = 3 p + 3
5 u - 3 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 9 =
3 p --- (3)
(2) = (3)
5 u - 3 = 3 u + 9
5 u - 3 u = 9 + 3
2 u = 12
1 u = 12 ÷ 2 = 6
Number of marbles in the container
= (1 u + 3) + 5 u
= 6 u + 3
= (6 x 6) + 3
= 36 + 3
= 39
Answer(s): 39