There are some white and brown marbles in a box. If 10 white marbles are removed from the box, the total number of marbles left will be 9 times the number of white marbles left. If 5 brown marbles are removed from the box, the total number of marbles left will be 4 times the number of white marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
White marbles |
Brown marbles |
White marbles |
Brown marbles |
Before |
1 u + 10 |
8 u |
1 p |
3 p + 5 |
Change |
- 10 |
|
|
- 5 |
After |
1 u |
8 u |
1 p |
3 p |
Number of brown marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of white marbles in the end for Case 2
= 4 p - 1 p
= 3 p
The number of white marbles at first is the same for Case 1 and Case 2.
The number of brown marbles at first is also the same for Case 1 and Case 2.
1 u + 10 = 1 p --- (1)
8 u = 3 p + 5
8 u - 5 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 30 =
3 p --- (3)
(2) = (3)
8 u - 5 = 3 u + 30
8 u - 3 u = 30 + 5
5 u = 35
1 u = 35 ÷ 5 = 7
Number of marbles in the box
= (1 u + 10) + 8 u
= 9 u + 10
= (9 x 7) + 10
= 63 + 10
= 73
Answer(s): 73