There are some blue and grey marbles in a container. If 7 blue marbles are removed from the container, the total number of marbles left will be 6 times the number of blue marbles left. If 10 grey marbles are removed from the container, the total number of marbles left will be 3 times the number of blue marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Blue marbles |
Grey marbles |
Blue marbles |
Grey marbles |
Before |
1 u + 7 |
5 u |
1 p |
2 p + 10 |
Change |
- 7 |
|
|
- 10 |
After |
1 u |
5 u |
1 p |
2 p |
Number of grey marbles in the end for Case 1
= 6 u - 1 u
= 5 u
Number of blue marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of blue marbles at first is the same for Case 1 and Case 2.
The number of grey marbles at first is also the same for Case 1 and Case 2.
1 u + 7 = 1 p --- (1)
5 u = 2 p + 10
5 u - 10 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 14 =
2 p --- (3)
(2) = (3)
5 u - 10 = 2 u + 14
5 u - 2 u = 14 + 10
3 u = 24
1 u = 24 ÷ 3 = 8
Number of marbles in the container
= (1 u + 7) + 5 u
= 6 u + 7
= (6 x 8) + 7
= 48 + 7
= 55
Answer(s): 55