There are some blue and white marbles in a container. If 6 blue marbles are removed from the container, the total number of marbles left will be 9 times the number of blue marbles left. If 20 white marbles are removed from the container, the total number of marbles left will be 5 times the number of blue marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Blue marbles |
White marbles |
Blue marbles |
White marbles |
Before |
1 u + 6 |
8 u |
1 p |
4 p + 20 |
Change |
- 6 |
|
|
- 20 |
After |
1 u |
8 u |
1 p |
4 p |
Number of white marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of blue marbles in the end for Case 2
= 5 p - 1 p
= 4 p
The number of blue marbles at first is the same for Case 1 and Case 2.
The number of white marbles at first is also the same for Case 1 and Case 2.
1 u + 6 = 1 p --- (1)
8 u = 4 p + 20
8 u - 20 =
4 p --- (2)
Make p the same.
(1)
x4 4 u + 24 =
4 p --- (3)
(2) = (3)
8 u - 20 = 4 u + 24
8 u - 4 u = 24 + 20
4 u = 44
1 u = 44 ÷ 4 = 11
Number of marbles in the container
= (1 u + 6) + 8 u
= 9 u + 6
= (9 x 11) + 6
= 99 + 6
= 105
Answer(s): 105