There are some black and yellow beads in a box. If 7 black beads are removed from the box, the total number of beads left will be 8 times the number of black beads left. If 23 yellow beads are removed from the box, the total number of beads left will be 4 times the number of black beads. How many beads are there in the box?
|
Case 1 |
Case 2 |
|
Black beads |
Yellow beads |
Black beads |
Yellow beads |
Before |
1 u + 7 |
7 u |
1 p |
3 p + 23 |
Change |
- 7 |
|
|
- 23 |
After |
1 u |
7 u |
1 p |
3 p |
Number of yellow beads in the end for Case 1
= 8 u - 1 u
= 7 u
Number of black beads in the end for Case 2
= 4 p - 1 p
= 3 p
The number of black beads at first is the same for Case 1 and Case 2.
The number of yellow beads at first is also the same for Case 1 and Case 2.
1 u + 7 = 1 p --- (1)
7 u = 3 p + 23
7 u - 23 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 21 =
3 p --- (3)
(2) = (3)
7 u - 23 = 3 u + 21
7 u - 3 u = 21 + 23
4 u = 44
1 u = 44 ÷ 4 = 11
Number of beads in the box
= (1 u + 7) + 7 u
= 8 u + 7
= (8 x 11) + 7
= 88 + 7
= 95
Answer(s): 95