There are some black and green marbles in a container. If 2 black marbles are removed from the container, the total number of marbles left will be 5 times the number of black marbles left. If 6 green marbles are removed from the container, the total number of marbles left will be 3 times the number of black marbles. How many marbles are there in the container?
|
Case 1 |
Case 2 |
|
Black marbles |
Green marbles |
Black marbles |
Green marbles |
Before |
1 u + 2 |
4 u |
1 p |
2 p + 6 |
Change |
- 2 |
|
|
- 6 |
After |
1 u |
4 u |
1 p |
2 p |
Number of green marbles in the end for Case 1
= 5 u - 1 u
= 4 u
Number of black marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of black marbles at first is the same for Case 1 and Case 2.
The number of green marbles at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
4 u = 2 p + 6
4 u - 6 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 4 =
2 p --- (3)
(2) = (3)
4 u - 6 = 2 u + 4
4 u - 2 u = 4 + 6
2 u = 10
1 u = 10 ÷ 2 = 5
Number of marbles in the container
= (1 u + 2) + 4 u
= 5 u + 2
= (5 x 5) + 2
= 25 + 2
= 27
Answer(s): 27