There are some pink and silver balls in a container. If 8 pink balls are removed from the container, the total number of balls left will be 9 times the number of pink balls left. If 6 silver balls are removed from the container, the total number of balls left will be 4 times the number of pink balls. How many balls are there in the container?

	Case 1		Case 2
	Pink balls	Silver balls	Pink balls	Silver balls
Before	1 u + 8	8 u	1 p	3 p + 6
Change	- 8			- 6
After	1 u	8 u	1 p	3 p

Number of silver balls in the end for Case 1
= 9 u - 1 u
= 8 u

Number of pink balls in the end for Case 2
= 4 p - 1 p
= 3 p

The number of pink balls at first is the same for Case 1 and Case 2.
The number of silver balls at first is also the same for Case 1 and Case 2.

1 u + 8 = 1 p --- (1)

8 u = 3 p + 6
8 u - 6 = 3 p --- (2)

Make p the same.

(1)_x3
3 u + 24 = 3 p --- (3)

(2) = (3)
8 u - 6 = 3 u + 24
8 u - 3 u = 24 + 6
5 u = 30

1 u = 30 ÷ 5 = 6

Number of balls in the container
= (1 u + 8) + 8 u
= 9 u + 8
= (9 x 6) + 8
= 54 + 8
= 62

Answer(s): 62