There are some green and red marbles in a box. If 4 green marbles are removed from the box, the total number of marbles left will be 9 times the number of green marbles left. If 34 red marbles are removed from the box, the total number of marbles left will be 3 times the number of green marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Green marbles |
Red marbles |
Green marbles |
Red marbles |
Before |
1 u + 4 |
8 u |
1 p |
2 p + 34 |
Change |
- 4 |
|
|
- 34 |
After |
1 u |
8 u |
1 p |
2 p |
Number of red marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of green marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of green marbles at first is the same for Case 1 and Case 2.
The number of red marbles at first is also the same for Case 1 and Case 2.
1 u + 4 = 1 p --- (1)
8 u = 2 p + 34
8 u - 34 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 8 =
2 p --- (3)
(2) = (3)
8 u - 34 = 2 u + 8
8 u - 2 u = 8 + 34
6 u = 42
1 u = 42 ÷ 6 = 7
Number of marbles in the box
= (1 u + 4) + 8 u
= 9 u + 4
= (9 x 7) + 4
= 63 + 4
= 67
Answer(s): 67