There are some red and white marbles in a box. If 3 red marbles are removed from the box, the total number of marbles left will be 9 times the number of red marbles left. If 30 white marbles are removed from the box, the total number of marbles left will be 3 times the number of red marbles. How many marbles are there in the box?
|
Case 1 |
Case 2 |
|
Red marbles |
White marbles |
Red marbles |
White marbles |
Before |
1 u + 3 |
8 u |
1 p |
2 p + 30 |
Change |
- 3 |
|
|
- 30 |
After |
1 u |
8 u |
1 p |
2 p |
Number of white marbles in the end for Case 1
= 9 u - 1 u
= 8 u
Number of red marbles in the end for Case 2
= 3 p - 1 p
= 2 p
The number of red marbles at first is the same for Case 1 and Case 2.
The number of white marbles at first is also the same for Case 1 and Case 2.
1 u + 3 = 1 p --- (1)
8 u = 2 p + 30
8 u - 30 =
2 p --- (2)
Make p the same.
(1)
x2 2 u + 6 =
2 p --- (3)
(2) = (3)
8 u - 30 = 2 u + 6
8 u - 2 u = 6 + 30
6 u = 36
1 u = 36 ÷ 6 = 6
Number of marbles in the box
= (1 u + 3) + 8 u
= 9 u + 3
= (9 x 6) + 3
= 54 + 3
= 57
Answer(s): 57