There are some grey and white beads in a box. If 2 grey beads are removed from the box, the total number of beads left will be 6 times the number of grey beads left. If 18 white beads are removed from the box, the total number of beads left will be 4 times the number of grey beads. How many beads are there in the box?
|
Case 1 |
Case 2 |
|
Grey beads |
White beads |
Grey beads |
White beads |
Before |
1 u + 2 |
5 u |
1 p |
3 p + 18 |
Change |
- 2 |
|
|
- 18 |
After |
1 u |
5 u |
1 p |
3 p |
Number of white beads in the end for Case 1
= 6 u - 1 u
= 5 u
Number of grey beads in the end for Case 2
= 4 p - 1 p
= 3 p
The number of grey beads at first is the same for Case 1 and Case 2.
The number of white beads at first is also the same for Case 1 and Case 2.
1 u + 2 = 1 p --- (1)
5 u = 3 p + 18
5 u - 18 =
3 p --- (2)
Make p the same.
(1)
x3 3 u + 6 =
3 p --- (3)
(2) = (3)
5 u - 18 = 3 u + 6
5 u - 3 u = 6 + 18
2 u = 24
1 u = 24 ÷ 2 = 12
Number of beads in the box
= (1 u + 2) + 5 u
= 6 u + 2
= (6 x 12) + 2
= 72 + 2
= 74
Answer(s): 74